Mathematics · Introduction to Trigonometry · NCERT Examples

Example 5

A complete, independently verified solution for NCERT Example 5.

ChapterResourceExercise / Example

Change resourceExample 5

ChapterResourceExercise / Example

Mathematics · Chapter 8 · NCERT Examples

Verified NCERT questions and solutionsSolutions are checked independently and follow the supplied NCERT chapter edition.

NCERT Example

right triangle · trigonometric ratios

In right triangle OPQ, right-angled at P, OP = 7 cm and OQ − PQ = 1 cm. Find sin Q and cos Q.

Board-exam working:

Let PQ = x cm. Then OQ = x + 1 cm.

OQ^2=OP^2+PQ^2

(x+1)^2=7^2+x^2

x^2+2x+1=49+x^2

2x=48\Rightarrow x=24

PQ=24\text{ cm},\qquad OQ=25\text{ cm}

\sin Q=\frac{OP}{OQ}=\frac7{25}

\cos Q=\frac{PQ}{OQ}=\frac{24}{25}

\sin Q=\frac7{25},\qquad \cos Q=\frac{24}{25}

Padhona AI