Mathematics · Arithmetic Progressions · NCERT Examples

Example 12

A complete, independently verified solution for NCERT Example 12.

Mathematics · Chapter 5 · NCERT Examples

Verified NCERT questions and solutionsSolutions are checked independently and follow the supplied NCERT chapter edition.

NCERT Example

Example 12

The sum of the first 14 terms is 1050 and the first term is 10. Find the 20th term.

Solution

Board-exam working:

Sn=n2[2a+(n−1)d]=n2(a+l)S_n=\frac{n}{2}[2a+(n-1)d]=\frac{n}{2}(a+l)

Given a=10,n=14,S₁₄=1050.

Use Sₙ=n/2[2a+(n−1)d].

1050=14/2[2×10+13d]=7(20+13d)=140+91d.

Thus 91d=910 and d=10.

Now a₂₀=a+19d=10+19×10=10+190=200.

Final answer

200.

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