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Mathematics · Arithmetic Progressions · NCERT Examples

Example 11

A complete, independently verified solution for NCERT Example 11.

Mathematics · Chapter 5 · NCERT Examples

Verified NCERT questions and solutionsSolutions are checked independently and follow the supplied NCERT chapter edition.

NCERT Example

Example 11

Find the sum of the first 22 terms of 8,3,−2,…

Solution

Board-exam working:

Sn=n2[2a+(n1)d]=n2(a+l)S_n=\frac{n}{2}[2a+(n-1)d]=\frac{n}{2}(a+l)

Here a=8,d=3−8=−5,n=22.

S₂₂=22/2[2×8+(22−1)(−5)]=11[16−105]=11(−89)=−979.

The last term is a₂₂=8+21(−5)=−97, and 22/2(8−97)=11(−89)=−979, confirming the sum.

Final answer

−979.