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Mathematics · Arithmetic Progressions · NCERT Examples

Example 8

A complete, independently verified solution for NCERT Example 8.

Mathematics · Chapter 5 · NCERT Examples

Verified NCERT questions and solutionsSolutions are checked independently and follow the supplied NCERT chapter edition.

NCERT Example

Example 8

Find the 11th term from the end of 10,7,4,…,−62.

Solution

Board-exam working:

an=a+(n1)da_n=a+(n-1)d

Here a=10,d=−3,l=−62.

First find the number of terms: −62=10+(n−1)(−3)=13−3n.

Thus 3n=75 and n=25.

The 11th term from the end is term number 25−11+1=15 from the start.

a₁₅=10+(15−1)(−3)=10−42=−32.

Check from the end: −62+(11−1)3=−62+30=−32.

Final answer

−32.