Mathematics · Arithmetic Progressions · NCERT Examples

Example 14

A complete, independently verified solution for NCERT Example 14.

Mathematics · Chapter 5 · NCERT Examples

Verified NCERT questions and solutionsSolutions are checked independently and follow the supplied NCERT chapter edition.

NCERT Example

Example 14

Find (i) the sum of the first 1000 positive integers and (ii) the sum of the first n positive integers.

Solution

Board-exam working:

Sn=n2[2a+(n−1)d]=n2(a+l)S_n=\frac{n}{2}[2a+(n-1)d]=\frac{n}{2}(a+l)

The positive integers form an AP with a=1,d=1.

Use Sₙ=n(a+l)/2.

(i) Here n=1000 and l=1000.

S₁₀₀₀=1000/2(1+1000)=500×1001=500500.

(ii) For the first n positive integers, l=n.

Therefore Sₙ=n/2(1+n)=n(n+1)/2.

Final answer

(i) 500500; (ii) n(n+1)/2.

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